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NBA Free Agency: Al Jefferson, Bobcats Agree To Deal

March 7, 2012; Charlotte, NC, USA; Utah Jazz center Al Jefferson (25) drives past Charlotte Bobcats center Bismack Biyombo (0) during the game at Time Warner Cable Arena. Mandatory Credit: Sam Sharpe-USA TODAY Sports

The Charlotte Bobcats have made a rare splash in free agency, agreeing to a deal with former Utah Jazz big man Al Jefferson.

According to ESPN’s Marc Stein, the deal is worth $41 million over three years. Stein, citing sources, also reports there is an opt-out after the second year of the contract.

Jefferson, 28, averaged 17.8 points, 9.2 rebounds, 2.1 assists and 1.1 blocks per game for the Jazz last season. He shot 49.4% from the field and 77.0% from the free throw line.

As you can see by the numbers, Jefferson is obviously a gifted scorer. Obviously, the teams needs scoring (the Bobcats had the third-worst offense in the league), so in that light, it makes sense.

However, he is not a good defender in any way shape or form. With the Bobcats far from the playoffs (they were 21-61, second-worst in the league), this move is a bit of a head-scratcher.

Jefferson was originally drafted by the Boston Celtics with the 15th overall pick in the first round of the 2004 draft. He spent three years with the Celtics before being dealt to Minnesota Timberwolves in the Kevin Garnett trade. After three years in Minnesota, Jefferson joined the Jazz in 2010.

 UPDATE: According to David Aldridge, the Bobcats will use the amnesty clause on forward Tyrus Thomas to make room for Jefferson.

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Topics: Al Jefferson, Charlotte Bobcats, NBA Free Agency

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