Los Angeles Lakers guard Kobe Bryant is still one of the more sexier names in all the NBA. But sexier, and notoriety, doesn’t exactly translate to value.
And when it comes to trade value, Kobe Bryant — potentially the second most popular player in the NBA — has none of it. At least according to one “anonymous’ NBA general manager.
Seven months after he ruptured his left Achilles tendon—and three weeks before he fractured his left kneecap—Bryant signed a $48.5 million, two-year deal. The contract, widely derided as the worst in the game, makes Bryant nearly impossible to move, even were the Lakers to try. Asked about Kobe’s value on the market, one GM answers definitively: “Zero. Look at that number. Who takes him?”
Kobe has played a grand total of six games in the last 16 months — averaging 13 points and six assists in those affairs. And with the contract that the Lakers hand-picked to offer Kobe (two-years, $48.5 million), it just makes teams even more weary of trading (in a hypothetical world) for such type of player — despite what his history book may state.
Then again, what Kobe has done for the Lakers franchise is invaluable. Los Angeles, in their thinking, can’t put a price tag on it. So much so, that if Kobe actually retires as a Laker, he’s still going to be, in some way or form, apart of the Lakers franchise for many years to come.
At least, that’s what you would expect. In five, six and seven years from now, will the Lakers will still be cutting Kobe a hefty check? Probably so.
Would other teams be lining up for that type of deal? Probably not. Which explains why Kobe is still immensely valuable to the Lakers and not so valuable to any other team in the NBA.
It’s a surprising statement to say that Kobe has “zero” trade value, sure, but it makes sense. Because, why would he?
Kobe will always be a Laker, and a quite important one, whether that means he’s playing 30 minutes a night or simply watching from the sideline in a suit.